Please help me with this problem. Figure 28-46 shows a wood cylinder of mass m=0

Question

Please help me with this problem.

Figure 28-46 shows a wood cylinder of mass m=0.250 kg length L = 0.100 m, with N = 10.0 turns of wire wrapped around it longitudinally, so that the plane of the wire coil contains the long central axis of the cylinder. The cylinder is released on a plane inclined at an angle theta to the horizontal, with the plane of the coil parallel to the incline plane. If there is a vertical uniform magnetic field of magnitude 0.500 T. what is the least current i through the coil that keeps the cylinder from rolling down the plane?

Explanation / Answer

magnetic force on coil is balanced by gravitational force

Fb = m*g*sintheta

N*I*L*B*sintheta = m*g*sintheta

I*0.1*0.5 = 0.25*9.8

I = 49 A <<<<<<-----------------answer

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