3-6. A 78 kg person stands in an elevator. 3. The elevator is at rest. What is t

Question

3-6. A 78 kg person stands in an elevator. 3. The elevator is at rest. What is the magnitude of the net force on the person? 4. The elevator is at rest. What s the magnitude of the normal force of the floor on the person? 5. The elevator and person have an upward acceleration of 1.80 m/s^2. What is the magnitude of the force of the FLOOR on the PERSON? 6. The elevator and person have an upward acceleration of 1.80 m/s^2. Consider the following statements about the force of the PERSON on the FLOOR.

Explanation / Answer

3. I would say that exerted from the floor of the elevator (usually called normal reaction:N): N=mg~780N

But if considering also the Earth, acting with G on the person, these 2 forces compensate and the total force on the person is 0N.

4. See point 3.

5. ma=N-G --> N=G+ma=m(g+a)~904.8N (or 920N if consider g=10m/s2)

6. II is true. See also point 5 for the magnitude of the force.

e is correct.

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