A 0.470-kg block is attached to a horizontal spring that is at its equilibrium l

Question

A 0.470-kg block is attached to a horizontal spring that is at its equilibrium length, and whose force constant is 25.0 N/m . The block rests on a frictionless surface. A 5.80×10?2-kg wad of putty is thrown horizontally at the block, hitting it with a speed of 2.50 m/s and sticking.

How far does the putty-block system compress the spring?

Problem 9.34 Part A A 0.470-kg block is attached to a horizontal spring that is at its equilibrium length, and whose force constant is 25.0 N/m. The block rests on a frictionless surface. A 5.80x102-kg wad of putty is thrown horizontally at the block, hitting it with a speed of 2.50 m/s and sticking How far does the putty-block system compress the spring? .- max max = cm Submit My Answers Give Up

Explanation / Answer

conservtion of momentum m1u1 +m2u2 = (m1+m2)V

so

0.47 * 0 + ( 5.8 e-2 * 2.5 ) = ( 0.47 + 5.8 e -2 ) * V

V = 0.274 m /s

also KE = PE

0.5 kx^2 = 0.5 mv^2

kx^2 = mv^2

25 * x^2 = ( 0.47 + 5.8e-2 ) * 0.274^2

x = 0.0398 = 3.98 cm--------<<<<<<<<<<<<<Answer

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