A candle is placed 0.560m in front of a converging lens. The image of the object
ID: 1458683 • Letter: A
Question
A candle is placed 0.560m in front of a converging lens. The image of the object is focused on a screen 0.389m behind the lens.A) What is the focal length of the lens?
B) What is the magnification of the image? (if the image is inverted, the magnification should be negative)
A candle is placed 0.560m in front of a converging lens. The image of the object is focused on a screen 0.389m behind the lens.
A) What is the focal length of the lens?
B) What is the magnification of the image? (if the image is inverted, the magnification should be negative)
A) What is the focal length of the lens?
B) What is the magnification of the image? (if the image is inverted, the magnification should be negative)
B) What is the magnification of the image? (if the image is inverted, the magnification should be negative)
Explanation / Answer
1/v + 1/u = 1/f
=> 1/0.560 - 1/0.389 = 1/f
=> f = -0.784 m
B) magnification = v/u = - 0.389/0.560 = - 0.694
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