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Wheels A and B in Figure 1 are connected by a belt that does not slip. The radiu

ID: 1458515 • Letter: W

Question

Wheels A and B in Figure 1 are connected by a belt that does not slip. The radius of wheel B is three times the radius of wheel A. What would be the ratio of the rotational inertias IA/IB if the two wheels had (a) the same angular momentum about their central axis and (b) the same rotational kinetic energy?

Wheels A and B in Figure 1 are connected by a belt that does not slip. The radius of wheel B is three times the radius of wheel A. What would be the ratio of the rotational inertias IA/IB if the two wheels had (a) the same angular momentum about their central axis and (b) the same rotational kinetic energy?

Explanation / Answer

Let us consdier

The mass of the wheel A =m1

The mass of the wheel B =m2

Given that radius of A =R

Radius of B =3R

a)

Since both the wheels are joined to the same belt then the system has the same linear velocity

VA =VB

we know that v =rw then

wARA =wBRB

wA/wB =3R/R

wA/wB =3-------(1)

Now from the conservation of angular momentum

LA =LB

IAwA =IBwB

IA/IB =wB/wA =(1/3) from equation (1)

Now from the conservation of energy

KEA =KEB

(1/2)IAwA2 =(1/2)IBwB2

IA/IB =(wB/wA)2

IA/IB =(1/3)2

IA/IB =1/9

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