A particular satellite was placed in a circular orbit about 268 mi above earth.

Question

A particular satellite was placed in a circular orbit about 268 mi above earth. Determine the orbital speed of the satellite. m/s Determine the time required for one complete revolution. Suppose a 1,700-kg car passes over a bump in a roadway that follows the arc of a circle of radius 26.0 m as in the figure below. What force does the road exert on the car as the car passes the highest point of the bump if the car travels at m/s^2 (neglect any friction that may occur) magnitude kN direction What is the maximum speed the car can have losing contact with the road as it passes this highest point?

Explanation / Answer

12
   a) height of the satellite h = 268 miles = 268*1.6 = 428.8 km from the surface of earth
   formula is V= sqrt(GM/R+h)
                      = sqrt(6.67*10^-11*6*10^24 /(6.38*10^6 + 0.428*10^6))
              =7667.058 m/s

   b) time period is T = 2*pi*sqrt(R^3/G*M)

                T = 2*3.14*sqrt((6.808*10^6)^3/(6.67*10^-11*6*10^24)) = 5576.355 s
               = 5576.35/86400 = 0.06454 days

13.     a) car mass 1700 kg, radius 26 m

       v =9.05 m/s
     here Fc = mg - N
   N= mg- mv^2/r

       N = mg- mv^2 /r = 1700*9.8 - (1700*9.05^2 / 26) =16660- 5355.163 N
               = 11304.837 N

   b)    The car will just begin to leave the road when the normal force becomes zero, so:

   0 = m(g - v²/r)
   v² / r = g
   v = gr = sqrt(9.8*26)
          = 15.9624 m/s

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.