A particle moves parallel to the x-axis. the net force on the particle increases

Question

A particle moves parallel to the x-axis. the net force on the particle increases with x according to the formula Fx=(260N/m)x, where the force is in newtons when x is in meters. ow much work does this force do on the particle as t moves from x=0 to x= 0.50m? A particle moves parallel to the x-axis. the net force on the particle increases with x according to the formula Fx=(260N/m)x, where the force is in newtons when x is in meters. ow much work does this force do on the particle as t moves from x=0 to x= 0.50m? A particle moves parallel to the x-axis. the net force on the particle increases with x according to the formula Fx=(260N/m)x, where the force is in newtons when x is in meters. ow much work does this force do on the particle as t moves from x=0 to x= 0.50m?

Explanation / Answer

by the definition of work done

W= F.S

Fx = (260 N/m) x

now work done in moving particle from x=0 to x=0.5 m is

W = 260*(0.5 -0)= 130 J

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