Please help by explaining with steps and diagrams if needed. Thank you. Q4: A pa

Question

Please help by explaining with steps and diagrams if needed. Thank you.

Q4: A parallel plate capacitor of capacitance C0 has plates of area A with separation d between them. When it is connected to a battery of voltage delta V0, it has charge of magnitude Q0 on its plates and the energy stored is U0. While it is connected to the battery the space between the plates is filled with a material of dielectric constant 2. After the dielectric is added, the magnitude of the charge on the plates and the energy stored in it are a. Q0, U0 b. 2Q0, U0 C. Q0, 2U0 d. 2Q0, 2U0 e. 2Q0, U0/2

Explanation / Answer

capacitor, Co

plate area, A

separation, d

battery voltage =Vo

charge=qo

qo=co*v

energy stored Uo

and

C=eo*A/d

now,

dielectric constant k=2

if battery is connected ,

new energy U'=k*Uo=2Uo

and

new charge q'=C'*V

q'=kCo*v

q'=2*co*V

q'=2qo

henec option d is correct option

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