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according to nuclear theory the average radius of a nuleus is given by R=1.2x10^

ID: 1457596 • Letter: A

Question

according to nuclear theory the average radius of a nuleus is given by R=1.2x10^-13 A^1/3cm where A is the atomic mass number of the isotope. find the radius of each stable isotope.Multiply each radius by the percent of the natural abundance

lead- 204 R(cm)________

lead-206 R(cm)_________

lead-207 R(cm)_________

lead-208 R(cm)___________

B) what is the natural % abundance for each isotope above

C) what are the weighted R(cm)

D) what is the total weighted R(cm)

E) what is the weightes average R(cm)

F) divide the larger of the estimated radius or weighted average by the other. what is your relative comparison ration =___________

Explanation / Answer

(a)

The radius of the lead-204 is,

R = R0A1/3 = [1.2x10^-13 ][204]1/3 = 7.064x10-13 cm

The radius of the lead-206 is,

R = R0A1/3 = [1.2x10^-13 ][206]1/3 = 7.087x10-13 cm

  The radius of the lead-207 is,

R = R0A1/3 = [1.2x10^-13 ][207]1/3 = 7.098x10-13 cm

The radius of the lead-208 is,

R = R0A1/3 = [1.2x10^-13 ][208]1/3 = 7.11x10-13 cm