Question Part Points Submissions Used A group of students, performing the same \

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A group of students, performing the same "Uniform Circular Motion" experiment that you performed in lab, obtained the following results.

r (m) mh (kg) t (s)
0.1825 0.06625 98.49
0.2430 0.0965 94.16
0.2610 0.1055 93.33
0.2980 0.124 96.99
0.3425 0.14625 90.81

For this table, r is the distance from the center of rotation to the radius indicator (i.e., the post that marks the position of the center of the bob during rotation), mh is the total hanging mass (including the hanger), and t is the time required for 50 complete rotations.
(a) Use Excel to construct a spreadsheet that show the following. (You will not submit this spreadsheet. However, the results will be needed later in this problem.)
(i) the above data

(ii) all calculations needed to compute the acceleration, a, for each trial [Hint]

(iii) a graph of mhg vs ac [Hint]

(iv) Use the trendline option to draw the best fit line and determine its slope. [Hint]

(b) Report this value below.
mass of the bob =  

Explanation / Answer

a) All we can help with in this forum is
(ii) acceleration a = v2 / r

v = 50 x 2pi x r / t
so a = 10000 x pi2 x r2 / (t2 x r)

a = 10000pi2 x r / t2
a = 98696 x r /t2
e.g. for the first trial
a = 98696 x 0.1825 / (98.49)2 = 1.86 m/s2

for the second trial
a = 98696 x 0.2430 / (94.16)2 = 2.71 m/s2

for the third trial
a = 98696 x 0.2610 / (93.33)2 = 2.96 m/s2

for the fourth trial
a = 98696 x 0.2980 / (96.99)2 = 3.13 m/s2

for the fifth trial
a = 98696 x 0.3425 / (90.81)2 = 4.1 m/s2

iii) We have now mh and ac values for each reading. So graph can be plotted.

iv) After plotting graph the slope can be easily find out by fitting parameters.

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