What is the length of a simple pendulum that oscillates with a period of 4.0 s o

Question

What is the length of a simple pendulum that oscillates with a period of 4.0 s on Earth, where the acceleration due to gravity is 9.80 m/s^2, and on Mars, where the acceleration due to gravity is 3.70 m/s^2 L_E = m L_M = m What mass would you need to suspend from a spring with a force constant of 20 N/m in order for the mass-spring system to oscillate with a period of 4.0 s on Earth, where the acceleration due to gravity is 9.80 m/s^2, and on Mars, where the acceleration due to gravity is 3.70 m/s^2 m_E = kg m_M = kg

Explanation / Answer

a) Period T = 2pi*sqrt(L/g). Plug in T and g.

L = length and g = acceleration due to gravity.

T=4s g=9.80m/s^2

b) Period T = 2pi * sqrt(m/k). Plug in T and k. Notice that g doesn't come into it.

k = force constant =20N/m

T=4s

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