A double slit experiment is set up using red light (lambda = 704 nm). A first or

Question

A double slit experiment is set up using red light (lambda = 704 nm). A first order bright fringe is seen at a given location on a screen. What wavelength of visible light (between 380 nm and 750 nm) would produce a dark fringe at the identical location on the screen? lambda = A new experiment is created with the screen at a distance of 1.8 m from the slits (with spacing 0.11 mm). What is the distance between the second order bright fringe of light with lambda = 692 nm and the third order bright fringe of light with A = 405 nm? (Give the absolute value of the smallest possible distance between these two fringes: the distance between bright fringes on the same side of the central bright fringe.) |x| =

Explanation / Answer

part a )

dsintheta = m*lambda

m =1

dsintheta = lambda = 704 nm

now given

it is equal to dark fringes

704nm = (m+1/2)*lambda

m = 0

lambda = 1408 nm

m = 1

lambda = 469.33

if m = 2

lambda = 281.6

so m = 1 will produce dark fringes

lambda = 469.33 nm

part 2 )

d*y/D = m*lambda

y = m*lambda*D/d

for second order

y = 2 * 692 * 10^-9 * 1.8 / 0.11 x 10^-3

y = 0.022647272 m

for m = 3 and lambda = 405 nm

y = 0.019881818

|dx| = 2.76545 x 10^-3 m

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