You set up an experiment with two polarizer screens on an optical bench and coll

Question

You set up an experiment with two polarizer screens on an optical bench and collect data for the intensity of the light at the detector as you vary the relative angle between the transmission axes of the polarizers. You create a plot of light intensity (in lux) vs cos2 ? with your data and get a linear fit for your graph gives a slope of 126.2 ± 2.204 and a y-intercept of 20.45 ± 1.141.

A.)What is intensity of the light source you used in your experiment? ANSWER IS NOT 40.90+-2.282 OR 126.2+-2.204

B.) What is ambient light in the room as you took your data? ANSWER IS NOT 20.45 +-1.141

You Set Up An Experiment With Two Polari Lab 8 - Postlab R Chegg Study | Guided Solutions and Stud DLE Faculty Support Student Services & SupportMoodle GROK myLSU LSU Libraries Hello Anastasiya Motuzok (Log out) PHYS 2109 for Dana Browne 109 for Dana BrowneLab 8Lab 8 Postlab R Question 1 Not complete Marked out of 4.00 You set up an experiment with two polarizer screens on an optical bench and collect data for the intensity of the light at the detector as you vary the relative angle between the transmission axes of the polarizers. You create a plot of light intensity (in lux vs cos2 with your data and get a linear fit for your graph gives a slope of 126.2 ± 2.204 and a y-intercept of 20.45 ± 1.141. (a) What is intensity of the light source you used in your experiment? (40.90 1-1 ))lux (b) What is ambient light in the room as you took your data? Flag question 2.282 20.45 ±| 1.141 lux Check Try again Next

Explanation / Answer

a) The intensity of the light source can be determined from the point when the transmission axes are aligned (0 degrees). This corresponds to the y-intercept of 20.45 ± 1.141. Only half of the light gets through however, as the other half is reflected by the polarises. Therefore the intensity of the light source is 40.90 +- 2.282.

b) The ambient light in the room can be obtained when the transmission axes are perpendicular to each other. That is, when theta = 90 degrees (or pi radians). This is because in this scenario, no light from the light source can pass through the polarisors, thus only ambient light is recorded. As you have not given the units of slope, I can't know whether you have used lux/radian or lux/degree. Basically however use the slope to determine the intensity when theta = 90 degrees, and you'll have the ambient light in the room.

Related Questions

Navigate

• Browse (All)
• Browse Y
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.