24,37 PART A (has right ANSWER) An insect 3.75 mm tall is placed 25.0 cm to the

Question

24,37 PART A (has right ANSWER) An insect 3.75 mm tall is placed 25.0 cm to the left of a thin planoconvex lens. The left surface of this lens is flat, the right surface has a radius of curvature of magnitude 12.2 cm , and the index of refraction of the lens material is 1.70. Part A Calculate the location of the image this lens forms of the insect. s = 57.5 cm S

Part B Calculate the size of the image. |y| = 8.63 mm

Part C Is the image real or virtual? erect or inverted? The image is real and inverted .

Part D Repeat part A if the lens is reversed. s = m cm SubmitMy AnswersGive Up Part E Repeat part B if the lens is reversed. |y| = m mm

NEED ANSER TO D AND E

Part E

Repeat part B if the lens is reversed.

Explanation / Answer

According to the question provided we know that

D) 1/f = ( n -1 ) * ( 1/r1 - 1/r2 )

1/f = ( 1.70 - 1) * ( 1/0 - 1/ 12.2 )

f = 17.4307 cm

d(i) = ( 1/f - 1/d(o) ) ^-1 = ( 1/17.4307 - 1/25 ) = 0.5757 m ==============ANSWER)

h(I) = - d(i) / d(o) * ( h (o) ) = ( -0.5757 m / 0.25 m ) * ( 3.75 mm ) = 8.63 mm =====ANSWER)

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