The buoyant force on an object submerged in a liquid is always equal to (he volu

Question

The buoyant force on an object submerged in a liquid is always equal to (he volume of the liquid displaced, equal to the weight of the object, equal to the weight of the liquid displaced, less than the volume of the liquid displaced. An object that sinks in water displaces a volume of water Steel has a density greater than water, but boats that are made out of steel float. How is this possible? An iron cube with a volume of 8.00 cm' is submerged in ethyl alcohol, which has a density of 0.806 g/cm Iron has a density of 7.86 g/cm What is the volume of ethyl alcohol displaced? What is the buoyant force on the cube? What is the cube's apparent weight in the ethyl alcohol?

Explanation / Answer

1. (c).

Arcimidese principle .

2.(a) .

Again by arcimides peinciple itit can be easily explained.

3. Because we design boat such that it displaces more weight of lequid than its own weight.

By acremedese princuple it is known that if a body displaces more liquid than its own weight then it does not ssink in the liquid .

4. (a). Volume of ethyl alcohol displaced = volume of cube itself = 8.00 cm3

(b). Buyont force on the cube = weight of liquid displaced = 8×0.806×9.8×10-3  N = 0.0632 N

(c). Apparent weight = own weight - buoyant force = 8×7.86×9.8×10-3 -0.0632 = 0.553 N

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