An aluminum ion enters a uniform magnetic field of magnitude 0.5T with a directi

Question

An aluminum ion enters a uniform magnetic field of magnitude 0.5T with a direction as shown in the figure and with a velocity of2.79*10^4m/s. this particular aluminum ion has a mass of 5.48*10^-26kg and follows a radius of 5.21mm.
Using the standard form for expressing change on ions(Al^+1, Al^+2,.....,Al^-1,Al^-2)what is the charge on the ion? m Formula st udent ID 27 kg 20) Light travels from air into an optical fiber with an index of refraction of 144 a. For the reflected ray, at what angle does it reflet? b. For the refracted ray, in which direction does the light bend c. If the angle of incidence on the end of the fiber is 22°', what is the angle of d. Sketch the path of light as it reflects and as it changes media. refraction inside the fiber? n 1.00 15 n2 = 1.44

Explanation / Answer

In a magnetic field

Fb = Fc

Fb = magnetic force

Fc = centripetal force

v = speed

q = charge

B = magnetoc field

r = radius of the circular path

q*v*B = m*v^2/r

r = m*v/qB

5.21*10^-3 = (5.48*10^-26*2.79*10^4/(q*0.5)

q = 5.87*10^-19 C

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