Help The solar wind is a thin, hot gas given off by the sun. Charged particles i

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The solar wind is a thin, hot gas given off by the sun. Charged particles in the gas enter the magnetic field of the Earth and can experience a magnetic force. Suppose that a charged particle traveling with a speed of 9xlOf,m/s encounters the Earth's magnetic field at an altitude where the field has a magnitude of 1.2x10 T. Assuming that the particle's velocity is perpendicular to the magnetic field, find the radius of the circular path on which the particle would move if it were (a) an electron ar.d (b)a proton.

Explanation / Answer

radius of the circular path r = (m*v)/(q*B)

m is the mass of the particle

v is the speed of the particle

q is the charge of the particle

B is the magnetic field

then for electron

radius r = (m*v)/(q*B) = (9.11*10^-31*9*10^6)/(1.6*10^-19*1.2*10^-7) = 427.03 m

then for proton

radius is r = (m*v)/(q*B) = (1.67*10^-27*9*10^6)/(1.6*10^-19*1.2*10^-7) = 782812.5 m

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