Suppose the isosceles prism of the figure has apex angle ? = 50.0° and index of

Question

Suppose the isosceles prism of the figure has apex angle ? = 50.0° and index of refraction n = 1.64. (a) What is the smallest angle of incidence ? for which a ray can enter the left face of the prism and exit the right face?  (b) What angle of incidence ? is required for the ray to exit the prism with an identical angle ? for its refraction, as it does in the figure?

Suppose the isosceles prism of the figure has apex angle = 50.0° and index of refraction n = 1.64. (a) what is the smallest angle of incidence for which a ray can enter the left face of the prism and exit the right face? (b) what angle of incidence is required for the ray to exit the prism with an identical angle for its refraction, as it does in the figure? o Number 38.73 (a) Number 38.73 UnitsT(degrees) UnitsT(degrees) (b) Number

Explanation / Answer

a) by snells law

Sin thetha0=n2/n1=1.64/1

Thetha0=arcsin(1.64)

B) thetha1=apex angle-arcsin(n1*sin thetha0/n2)

Thetha1=50-arcsin(1*arcsin(1.64)/1.64)

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.