please help me with all steps for the answer. thank you. A parallel plate capaci

Question

please help me with all steps for the answer. thank you.

A parallel plate capacitor has plates of area 2.0 times 10^-3 m^2 and plate separation 1.0 times 10^-4 m. Air fills the volume between the plates. What potential difference is required to establish a 3.0 muC charge on the plates? A battery is connected to a series combination of a switch, a resistor, and an initially uncharged capacitor. The switch is closed at t = 0. Which of the following statements is true? A 1.2 mu F capacitor in a flash camera is charged by a 1.5-V batters When the camera flashes, this capacitor is discharged through a resistor. The time constant of the circuit is 10 ms. What is the value of the resistance? If a current is flowing through a wire toward the west and the magnetic force on the wire is directed toward the north, what is the direction of the magnetic field vector? A 1.0-m long wire is carrying a certain amount of current. The wire is placed perpendicular to a magnetic field of strength 0.20 T. If the wire experiences a force of 0.60 N. what is the magnitude of the current moving through the wire? The SI unit of magnetic field is Tesla (T). This is equivalent to The apparatus in the figure consists of two parallel plates (shown on edge) and a large magnet (not shown). The field of the magnet is uniform and directed into the plane of the paper. What direction must the E field have so that positively charged particles entering from the left will traverse to the exit slit undeviated?

Explanation / Answer

13.

Q = CV

V = Q/C

C = e0*A/d

V = Q*d/e0*A

V = 3*10^-6*1*10^-4/(8.85*10^-12*2*10^-3)

V = 1.69*10^4 V = 1.7*10^4 V

15.

time constnat = RC

R = time constant/C = 10*10^-3/(1.2*10^-6) = 8.333*10^3 ohm

R = 8.33 k-ohm

17.

F = i*LXB = iLB sin A

sin A = 1 since perpendicular

i = F/LB

i = 0.6/1*0.2 = 3.0 Amp.

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.