1- a , b , c , d 3- a , b 1· The position versus time graph at right represents

Question

1- a , b , c , d
3- a , b
1· The position versus time graph at right represents the motion of an object moving in a straight line. 10 a. Describe the motion. During which periods of time, if any, is the velocity constant? Explain how you can tell. Find the object's instantaneous velocity at each of the following times. Show your work. b. Time (seconds) i. ,-0.5 s it 4.0s How does the method you used to answer parts i-iii rely on your answer to part a? c. For each of the following intervals, find the average velocity of the object. between A and C ii. between A and D ii. between B and D i. On the graph above, sketch and label the lines that would represent an object moving with constant velocity between each of the pairs of points in parts i-iii. For each line that you drew, how does the slope compare to the average velocity that you computed above? In which of the cases from part c, if any, is the average velocity over an interval equal to the average of the constant velocities occurring in that interval? [For example, is ac (the average velocity from. A to C) equal to 140at uac)?] d. Tutorials in Introductory Physics McDermott, Shaffer, & P.E.G., U. Wash. CPrentice Hall, Inc. First Edition, 2002

Explanation / Answer

1(a)

A to B , object is at rest since position of object remains same.

B to C object moves at constant velocity , since the slope of position -time graph represent velocity and it is constant

.C to D object moves at constant velocity lower than in B to C, Since slope in C to D is smaller as compared to B to C

b)

i)

at t = 0.5

instanteneous velocity = slope = 0  

ii)

at t = 2

instanteneous velocity = slope = height of BC / displacement of BC in horizontal = (8 - 2) / (3 - 1) = 3 m/s

iii)

ii)

at t = 4

instanteneous velocity = slope = height of CD / displacement of CD in horizontal = (10 - 8) / (5 - 3) = 1 m/s

c)

A to C :

average velocity = displacement A to C / time = (8 - 2) / (3 - 0) = 2 m/s

A to D :

average velocity = displacement A to D / time = (10 - 2) / 5 - 0) = 1.6 m/s

B to D :

average velocity = displacement B to D / time = (10 - 2) / 5 - 1) = 2 m/s

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.