You\'ve been asked to investigate an accident in which a 7600.00 kg bus collided

Question

You've been asked to investigate an accident in which a 7600.00 kg bus collided with a 1900.00 kg car. The bus crashed into the back of the car while the two were both traveling in the same direction. The bus was going 10.50 mi/hr. After the collision, the bus and car together skid to a halt over a distance of 1.29 meters. By researching the properties of the road surface, you determine that the car and bus skid to a halt, slowing down at a constant rate of 6.86 m/s22 .

Let KskidKskid be the change in the kinetic energy of the car and bus as they skid to a halt. Let askidaskid be the component of acceleration along the ground during the skid. Let xskidxskid be the displacement through which the car and bus skid. Let mbusmbus be the inertia of the bus and mcarmcar be the inertia of the car.

After compiling all of your earlier conclusions you want to determine the level of damage to the two vehicles. A reasonable proxy for this is the ratio of kinetic energy lost during the collision over the total original kinetic energy before the collision. You realize that in order to work this out you will first have to determine the speed of the car before the bus collided with it. What was the car's speed (in mi/hr)_________ and what is the damage to the vehicle________?

Explanation / Answer

mass of the car,mc=1900 kg

mass of the bus,mb=7600 kg

speed of bus before collission, vb=10.5 mi/ hr

Total mass=9500 kg

mc.vc+mb.vb=(mc+mb)*v

1900*vc+(7600*10.5)=9500*6.86

vc=7.7 mi/hr

This is a kind of inelastic collision . After the collision the colliding objects stick together and become one.

Involves the greatest loss of Kinetic Energy and the loss of KE then the energy will need to appear as heat and or sound. The colliding objects usually suffer some kind of permanent damage

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