Please answer PART B ONLY A uniform, 258-N rod that is 1.85 m long carries a 225

Question

Please answer PART B ONLY

A uniform, 258-N rod that is 1.85 m long carries a 225-N weight at its right end and an unknown weight W toward the left end (see the figure (Figure 1^). When W is placed 43.3 cm from the left end of the rod, the system just balances horizontally when the fulcrum is located 84.4 cm from the right end. Find W. W= 295 N If W is now moved 20.9 cm to the right, how far must the fulcrum be moved to restore balance? If W is now moved 20.9 cm to the right, in what direction must the fulcrum be moved to restore balance? to the left to the right

Explanation / Answer

B

The equilibrium condition is that the total momentum of all forces *relative to the fulcrum) should be 0.

Consider the distance (unknown) from the right extreme point to the new position of the fulcrum (distance between 225 N weight to the new position of the fulcrum) being x.

We have the eq:

Fg2x=Fg1(L/2-x)+W*(L-r1-r2-x) (1)

r1=0.433 m

r2=0.209 m

L=1.85 m

Fg2=225N

Fg1=258 N

W=295 N

Replace in (1) and get:

x~0.765 m

OBS: I got a wrong value firstly, because I forgot to substract x from the term in W (see eq(1)).

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