Six flags has an attraction that has the rider get into a basket which is 3.0 me

Question

Six flags has an attraction that has the rider get into a basket which is 3.0 meters from the rotation pole and the bottom of the basket hangs 5.0 meters below. The ride begins to rotate and the basket swings out to an angle of 35 degrees

(A) What is the radius of the circle the rider swings around?

(B) What is the velocity of the rider as they go around the ride?

(C) If the ride has you go around 100 times before you get off, how long will the ride last?

(D) What is the tension in the 5.0 meter long rail which is holding you to the ride?

Explanation / Answer

A)
r = 3 + 5*sin 35 = 5.87 m
Answer: 5.87 m

B)
T*cos 35 = m*g
T*sin 35 = m*v^2/r

divide 2nd equation by 1st:
tan 35 = v^2/(r*g)
0.7 = v^2 / (5.87*9.81)
v = 6.35 m/s
Answer: 6.35 m/s

C)
w = v/r
= 6.35/5.87
=1.08 rad/s

100 rev = 100*2*pi rad= 628.3 rad

t = 628.3 rad/1.08
= 582 s
= 9.7 minutes
Answer: 9.7 minutes

D)
I think mass of of rider has to given to solve this

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