In the problem above, the magnetic field was normal, i.e. it made an angle of 90

Question

In the problem above, the magnetic field was normal, i.e. it made an angle of 90 degrees with the plane of the loop ABCD. Now suppose the magnetic field makes an angle of 40o with the plane of the loop ABCD. Find the induced emf. (Assume the same flux density and velocity given before.)In the problem above, the magnetic field was normal, i.e. it made an angle of 90 degrees with the plane of the loop ABCD. Now suppose the magnetic field makes an angle of 40o with the plane of the loop ABCD. Find the induced emf. (Assume the same flux density and velocity given before.)In the problem above, the magnetic field was normal, i.e. it made an angle of 90 degrees with the plane of the loop ABCD. Now suppose the magnetic field makes an angle of 40o with the plane of the loop ABCD. Find the induced emf. (Assume the same flux density and velocity given before.)

Explanation / Answer

here

When the magnetic field makes an angle of 40° with the plane of the loop , the normal component to the plane is B*sin 40

so

emf = B * sin(40) * d * v

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