TRUE/FALSE. Fill in\"A\" if the statement is true and \"B\" if the statement is

Question

TRUE/FALSE. Fill in"A" if the statement is true and "B" if the statement is false 1) The direction of an electric field is from higher to lower potential. 2) Equipotential lines and electric field lines meet perpendicular to one another. 3) The electric field between the plates of a parallel plate capacitor is inversely proportional to the 1) 2) 3) plate separation. MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question 4) For a proton moving in the direction of the electric field 4) A) its potential energy decreases and its electric potential increases B) its potential energy decreases and its electric potential decreases C) its potential energy increases and its electric potential decreases D) its potential energy increases and its electric potential increases. E) both its potential energy and it electric potential remain constant. 5) Which of the following will increase the capacitance of a parallel plate capacitor? 5) A) an increase in the plate area and a decrease in the plate separation B) an increase in the potential difference between the plates C) a decrease in the potential difference between the plates D) a decrease in the plate area and an increase in the plate separation E) none of the above 6) A capacitor consists of a set of two parallel plates of area A separated by a distance d. This capacitor 6) is connected to a battery that maintains a constant potential difference between the plates. If the separation between the plates is doubled, the magnitude of the charge on the plates will A) not change. B) be cut in fourth. C) double. D) quadruple. E) be cut in half. 7) A dielectric material such as paper is placed between the plates of a capacitor holding a fixed 7) charge. What happens to the electric field between the plates? A) becomes weaker C) reduces to zero B) becomes stronger D) no change

Explanation / Answer

4) everything moves towards attaining lower potential energy

and del V = del U /q

so, the potential energy decreases as well as the electric potential decreases

option B) is the correct answer

5) capacitanec = Aeo/d

where A = area , d = plate sepeartion

C will increase when A increases and d decreases

so option A) is the correct answer

6) Q = Cv

when seperation is doubled , capacitance will be halved

which in turn will half the charge on the plates

option E) is the correct answer

7) when a dielectric is placed , Capacitance is increased

which means Q will increase

EF = Q/Aeo

Hence ,EF will also increase.

so , option B is the correct answer

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.