Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Question 4 of 6 Question 5 of 6 Question 6 of 6 Question 4 of 6 5.0 Points The s

ID: 1447208 • Letter: Q

Question

Question 4 of 6

Question 5 of 6

Question 6 of 6

Question 4 of 6

5.0 Points The strengths of the electric and magnetic fields inside the velocity selector are respectively E = 500 V/m and B1= 0.0200 T. What is the speed of the ions that are selected? A. 4.00 × 10-5 m/s B. 5.00 × 102 m/s C. 2.50 × 105 m/s D. 10.0 m/s E. 2.50 × 104 m/s Reset Selection

Question 5 of 6

5.0 Points The strength of the magnetic field inside the mass spectrometer is B2 = 5.00 × 10?3 T. If the radius of the trajectory of the ion is found to be r = 0.626 m, what was the charge to mass ratio q/m? A. 5.01 × 10?3 C/kg B. 2.00 × 106 C/kg C. 3.13 × 106 C/kg D. 7.83 × 105 C/kg E. 7.99 × 106 C/kg Reset Selection

Question 6 of 6

5.0 Points From the figure, can you tell whether the ion was positively charged or negatively charged? If yes, how? A. The ion was negatively charged. We can tell this from the direction that the ion curves in the mass spectrometer. B. The ion was negatively charged. We can tell this from the fact that the ion came straight through the velocity selector. C. The sign of the ion's charge cannot be determined from this experiment. D. The ion was positively charged. We can tell this from the fact that the ion came straight through the velocity selector. E. The ion was positively charged. We can tell this from the direction that the ion curves in the mass spectrometer.

Explanation / Answer

4)

V = speed = E/B1 = 500 / 0.02 = 25000 m/s = 2.5 x 104 m/s

5)

r = mv/(qB2)

q/m = v/(r B2) = 25000 / (0.626 x 0.005) = 7.99 x 106

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote