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t.php?attempt-1 $9 mysite.cbi.com Faculty Support Student Services& Support GROK m Hello Samu Lab 7: To leave Nicholson, you exit via the door to the quad. The door is 40 inches wide and has a mass of 200 kg You push the door with a perpendicular force of 51.99N exactly 0.91m away from the hinge. This generates the minimum torque, Ti, required to open the door If you pushed the door 0.15m away from the hinge, with what force (in N) must you push the door to supply the same torque? Answer. [ Check Hello Samuel Messina (Log out) 2016 Spring PHYS 2108 for Dana Browne

Explanation / Answer

Torque = Fr

and torque is same

So, F1r1 = F2r2

51.99 ×0.91 = F2 × 0.15

F2 =51.99×0.91/0.15 = 315.406 N Answer

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