A 4.0 cm -tall object is 12 cm in front of a converging lens that has a 20 cm fo

Question

A 4.0 cm -tall object is 12 cm in front of a converging lens that has a 20 cm focal length. Part A Calculate the image position. Express your answer using two significant figures. s = cm SubmitMy AnswersGive Up Incorrect; Try Again; 4 attempts remaining Part B Calculate the image height. Express your answer using two significant figures. h = cm SubmitMy AnswersGive Up Provide FeedbackContinue Incorrect. Incorrect; Try Again; 4 attempts remaining. No additional feedback. Introductory Physics II- 10Z1_79696 Help Close 09: Refraction Problem 18.31 « previous 7 of 8 next »

Explanation / Answer

use the basic lens equation:

1/p + 1/q = 1/f

p=object distance = +12 cm
q=image distance
f=focal length = +20 cm

1/12 + 1/q = 1/20

q = -30 cm

q=30 cm, so the image is 30 cm behind the converging lens (the sign convention for converging lenses is that positive image distances are behind the lens; positive object distances are in front of the lens)

the magnification is given by m = -30/12 =-2.5

Height = (4.0 cm)*-2.5
= 10 cm (inverted)

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