Violet light with = 430 nm strikes a pair of slits separated by 0.505 mm . Part

Question

Violet light with = 430 nm strikes a pair of slits separated by 0.505 mm .

Part A

On a screen 1.23 m away, what's the distance between the two second-order bright fringes?

Express your answer with the appropriate units.

Part B

On a screen 1.23 m away, what's the distance between the central maximum and one of the fourth dark fringes?

Express your answer with the appropriate units.

Part C

On a screen 1.23 m away, what's the distance between the third bright fringe on one side of the central maximum and the third dark fringe on the other?

Express your answer with the appropriate units.

Explanation / Answer

fringe width = D/d

therefore,   = 430 x 10-9 x 1.23 / ( 0.505 x 10-3 ) = 1.047326733 x 10-3 m

that is 1.0473 mm

a.) there are 4 fringes between the two second-order fringes of the pattern,

So, the distance between the two second-order fringes is 4 = 4.189306931 mm

b.) there are 3.5 fringes between the central maximum and one of the 4th dark fringe of the pattern,

So, the distance between them is 3.5 = 3.665643564 mm

c.) there are 3 + 2.5 = 5.5 fringes between the third bright fringe on one side and third dark fringe on the other side of the central maximum,

So, the distance between them is 5.5 = 5.76029703 mm

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