(hrw8c9p91) A pellet gun fires ten 2.4 g pellets per second with a speed of 580
ID: 1444312 • Letter: #
Question
(hrw8c9p91) A pellet gun fires ten 2.4 g pellets per second with a speed of 580 m/s . The pellets are stopped by a rigid wall. (a) What is the momentum of each pellet? (b) What is the kinetic energy of each pellet? (c) What is the average force exerted by the stream of pellets on the wall? (d) If each pellet is in contact with the wall for 0.60ms, what is the average force exerted on the wall by each pellet during contact? Why is this average force so different from the average force calculated in (c)?
Explanation / Answer
a. momentum of each pellet = 2.4*10^-3*580 = 1.392 kg m/s
b. k.e. of each pellet = 0.5*2.4*10^-3*580^2 = 403.68 J
c. Avg force = change in momentum per second = 10 * momentume of each pellet = 13.92 N
d. For the given time, avg force exerted by each pellet = momentum of each pellet / time = 2320 N
this is different than c because then it was considered that each bullet loses its momentum in 0.1 s (10 pellets per second), but in D its assumed that every bullet loses its momentum in lesser time (0.6ms)
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