hrw8c9p91) A pellet gun fires ten 2.5 g pellets per second with a speed of 600 m

Question

hrw8c9p91) A pellet gun fires ten 2.5 g pellets per second with a speed of 600 m/s . The pellets are stopped by a rigid wall. (a) What is the momentum of each pellet?

(b) What is the kinetic energy of each pellet?

(c) What is the average force exerted by the stream of pellets on the wall

(d) If each pellet is in contact with the wall for 0.60ms, what is the average force exerted on the wall by each pellet during contact? Why is this average force so different from the average force calculated in (c)?

Explanation / Answer

(a) The momentum of each pellet is 2.5g*600 m/s=0.0025*600= 1.5 kg m/s

(b) Kinetic energy of each pellet = (1/2)*m*v^2 = 0.5*0.0025*600^2 = 450 J

(c) F[avg]=p/t=(1.5 kg m/s per pellet * 10 pellets)/1 second=15 N

(d) F[avg]=(1.5 kg m/s )/0.0006= 2500 N

Above average force is so different from the average force calculated in (c) because there is a lot of time in between pellets when no force is exerted on the wall.

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