1) In the circuit below both meters are idealized, the battery has no appreciabl
ID: 1443004 • Letter: 1
Question
1) In the circuit below both meters are idealized, the battery has no appreciable internal resistance, and the ammeter reads 1.39 A. (Let R1 = 52.0 ?, R2 = 29.0 ?, and R3 = R4 = 19 ?.). What does the voltmeter read? What is the emf (i.e., the voltage) of the battery?
(Hint: Start with the parallel combination. There are six steps to solve the entire problem.)
2) In the circuit shown in the following figure, the voltage across the R1 = 7.00-? resistor is 21.0 V. What are the emf of the battery and the current through the 6.00-? resistor? (Let R2 = 1.00 ?.)
1. In the circuit below both meters are idealized, the battery has no appreciable internal resistance, and the ammeter reads 1.39 A. (Let R1-52.0 , R2 = 29.0 , and R-R4-19 ). What does the voltmeter read? What is the emf (ie., the voltage) of the battery? (Hint: Start with the parallel combination. There are six steps to solve the entire problem.) RI 10.0 5.02 In the circuit shown in the following figure, the voltage across the R1 7.00-2 resistor is 21.0 V. What are the emf of the battery and the current through the 6.00-Q resistor? (Let R2 1.00 ) 2. R R2 6.00 12 la the igure below, al Ri's 3. In the figure below, all R's are 50 and all R's are 25 What is the equivalent resistance of the combination?Explanation / Answer
part 1)
voltage at R2 I*R2 = 1.39 * 29 = 40.31 V
R3 , R4 in parallel with R2 so voltage drop remain same
I = at R3 = V/R3 = 40.31/19 = 2.12
I at R4 + 10 ohm combination = 40.31/29 = 1.39 A
total current = 1.39 + 2.12 + 1.39 = 4.9 A
it will be same for R1
V = IR1 = 4.9 * 52 = 254.8 ohm
req of R2 , R3 and R4
1/R' = 1/29 + 1/19 + 1/29
R' = 8.224
Req = R1 + R' + 35 = 95.224 ohm
emf of battery = I*Req = 95.224 * 4.9 = 466.6 V
part 2 )
current in R1 = 21/7 = 3 A
it will be same for R2 because R1 and R2 in series ,
voltage drop at R2 = 3 * 1 = 3 V
total voltage = 24 V
it will be same for 6 V ( in parallel )
current in 6A = 24/6 = 4 A
total emf of battery = 24 V
part 3 )
on right side first R1 and R2 in series = R= R1 + R2 = 75 ohm
now R in parallel with R2 = 1/R' = 1/75 + 1/25 = 18.75 ohm
now R' in series with R1 = R" = 18.75 + 50 = 68.75
R" in parallel with R2 = 1/R"' = 1/68.75 + 1/25
R"' = 18.33
R"' in seires with R1 = Req = 18.33 + 50 = 68.33 ohm
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