Given the following mass distribution m_n = 6.0 times 10^6 Kg at (x,y) = (0.0m,

Question

Given the following mass distribution m_n = 6.0 times 10^6 Kg at (x,y) = (0.0m, 0.0m) m_1 = -7.0 times 10^6kg at (x_1-y_1) = (4.0m, 4.0m) m_2 = -4.0 times 10^6 kg at (s_2-y_2)-(0.0m,4.0m) a) Draw the mass distribution on a coordinate system and show the direction the gravitional force F_01 and F_02 exerted by masses m_1 and m_2 respectively, on the mass m_0 b) Find the Vecot form of the force F_01 c) Find the vector form of the force F_02 d) Find the resultant force F_0 = F_0 + F_02 e) Draw f_0 on the coordinate system. f) Find the potential energy of the bound system of masses

Explanation / Answer

Mass of the neutron star:

M = 2 * Msun

   = 2 * 4.0x10^30

   = 8.0x10^30 kg

Radius of the neutron star:

R = 10 km

    = 10000 m

Escape velocity:

Ve = sqrt [ 2 G M / R ]

      = sqrt [ 2 * 6.67x10^-11 * 8.0x10^30 / 10000 ]

      = 3.3x10^8 m/s

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