a. 3/256 3/32 3/16 d. 3/8 e. 3/4 10. Rick identifies two populations of purebree
ID: 144233 • Letter: A
Question
a. 3/256 3/32 3/16 d. 3/8 e. 3/4 10. Rick identifies two populations of purebreeding winged Formics. Recalling that the winged allele (0 is recessive, he crosses the two populations. To his surprise, the things are kexpletive deleted> all wingless! Which of the following best explain these results? a. The falleles in the two populations are at the same locus. b. Multiple alleles at the F locus are segregating in one of the populations. c. The mutant alleles in the two populations are at different loci. d. The two populations have incomplete penetrance for the winged trait. e. Goat beards.Explanation / Answer
10. Mutants alleles in the two populations are at different loci. Lets say one pure bred population has a mutant allele at f1 locus and its genotype is f1f1 as its a recessive trait. Another population has a mutant allele at f2 locus and its genotype is f2f2.
The cross :f1f1 (winged) x f2f2 (winged)
progeny : f1f2 (wingless)
The progeny is heterozygous for mutant alleles (one copy of f1 and one copy of f2). These mutant recessive allele will only express when both are present in homzygous recessive form i.e f1f1 or f2f2
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