A cube of glass (n = 1.60) is immersed in water (n = 1.33). A ray of light trave

Question

A cube of glass (n = 1.60) is immersed in water (n = 1.33). A ray of light traveling in the glass is incident at a flat surface of the glass. What is the critical angle theta_C for internal reflection back into the glass? A ray of light traveling in water (n = 1.33) is incident at the flat surface of a block of glass (n = 1.60). If the incident ray in water makes an angle of 34.0 degree with the normal to the interface, what angle does the ray that is refracted into the glass make with the normal?

Explanation / Answer

As we know that the critical angle is given as

Here n1 = 1.33 and n2 = 1.6

Hence the angle will be

Angle = sin -1 (1.33/1.6) = 56.22 degree

Please post sepreate question seperately.Please write back in comments if you have any doubt in the solution. If you like the answer, i would appreciate a thumbs up.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.