Green light (? = 552 nm in vacuum) strikes the glass nearly perpendicular to the

Question

Green light (? = 552 nm in vacuum) strikes the glass nearly perpendicular to the plates. If the maximum separation of the glass plates is 4.10 x10 determine the following: A. How many bright fringes occur between the edge of the glass plates where they touch and the other edge where they are separated by maximum distance ­5 m, determine the following: B. Very briefly explain why there is a dark fringe where the plates touch.

Explanation / Answer

Here given

Green light wavelength () = 552nm

Separation of the plates (t) = 4.10x10-5m (but given is 4.1 x10)

number of bright fringes (m) = ?

Now formula

t = ((m+1/2)()) / 2

m =( 2t/ ()-1/2

m= (4.10x10-5/ 552x10-9) – ½

74.275-0.05

m = 74

first bright fringe at m=0 so that total bright fringes are 75

The dark fringe where the plates touch because of the destructive interference at that edges of the plates. This will be caused by the phase shift upon reflection of the wave reflection from the lower plate at a distance of zero (0).

m = (2 x 0)/ (552x10-9) -0.5

m= - 0.5 wavelength phase shift

Related Questions

Navigate

• Browse (All)
• Browse G
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.