Thin lenses. Object 0 stands on the central axis of a thin symmetric lens. For t

Question

Thin lenses. Object 0 stands on the central axis of a thin symmetric lens. For this situation, each problem in the table (below) gives object distance p (centimeters), the type of lens (C stands for converging and D for diverging), and then the distance (centimeters, without proper sign) between a focal point and the lens. Find the image distance i and the lateral magnification m of the object, including signs. Also, determine whether the image is real or virtual, inverted from object O or noninverted, and on the same side of the lens as object O or on the opposite side.

Explanation / Answer

a) for diverging lens, focal length is negative.

f = - 32 cm

object distance, o = 14 cm

using lens equation,

1/f = 1/o + 1/i

1/(-32) = 1/14 + 1/i

i = - 9.74 cm

B)magnification = - i/o = - (-9.74) / (14) = 0.70

C) diverging lens makes virtual images.

d) m is +ve hence image is noninverted.

e) it is on same side as object.

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