PE C https:// Assignment Responses/last? dep 13562875 Need Help? Read It Master

Question

PE C https:// Assignment Responses/last? dep 13562875 Need Help? Read It Master It Il Talk to a Tutor 4. C+D -10 points SerPSE8 28.P.013 My Notes Ask Your Teacher Consider the combination of resistors shown in the figure below. 4.00 202 5.0 8.00 6.0 m (a) Find the equivalent resistance between point a and b (b) If a voltage of 29.8 Vis applied between points a and b, find the current in each resistor. 12 S2 6 S2 5 S2 4 n 8 S2 Need Help? l Read It Talk to a Tutor 5. -10 points SerPSE8 28.P.015 My Notes Ask Your Teacher Two resistons connected in series have an equivalent resistance of 684.3 n. When they are connected in parallel, the equivalent resistance is 140.1 m. Find the resistance of each resistor. n (small resistance n (large resistance) Need Help? Read it Talk to a Tutor

Explanation / Answer

4 and 8 ohm are in parallel and their parallel combination is given as

R' = 4 x 8 / (4 + 8) = 2.7 ohm

Similarly , 12 and 6 ohm are in parallel and their parallel combination is given as

R'' = 12 x 6 / (12 + 6) = 4 ohm

R'' , 5 ohm and R' are in series and their series combination gives equivalent resistance which is given as

Requivalent = R'' + 5 + R' = 4 + 5 + 2.7 = 11.7 ohm

b)

Vab = 29.8 volts

i = Net current flowing

Using ohm's law

i = Vab /Requivalent = 29.8 / 11.7 = 2.55 A

V'' = Voltage across R'' = i R'' = 2.55 x 4 = 10.2 volts

V' = Voltage across R' = i R' = 2.55 x 2.7 = 6.885 volts

i12 = current in 12 ohm = V''/12 = 10.2 /12 = 0.85 A

i6 = current in 6 ohm = V''/6 = 10.2 /6= 1.7 A

i5 = current in 5 ohm = i = 2.55 A          since 5 ohm in series with R'' and R'

i4 = current in 4 ohm = V'/4 = 6.885 /4 = 1.72 A

i8 = current in 8 ohm = V'/8 = 6.885 /8= 0.86 A

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