the drawing shows a ray of light traveling through three materials whose surface
ID: 1439660 • Letter: T
Question
the drawing shows a ray of light traveling through three materials whose surfaces are parallel to each other. The refracted rays (but not the reflected rays) are shown as the light passes through each material. A ray of light strikes the a–b interface at a 50.0? angle of incidence. The index of refraction of material a is na = 1.20. The angles of refraction in materials b and c are, respectively, 38.7? and 60.4?. Find the indices of refraction in these two media.
I need the answer for nb and nc with units please. Please indicate the answer for both of these because a lot of the "chegg experts" just answer one part
Explanation / Answer
use snelles law na sinA = nb sin B
for B = 38.7 deg
nb = 1.2 * sin 50 /sin 38.7
nb = 1.47 is the refrative index of nb
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use snelles law na sinA = nb sin B
for B = 60.4 deg
nb = 1.2 * sin 50 /sin 60.4
nb = 1.057 is the refrative index of nb
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