a wire of length L and resistance R is now drawn out by pulling such that its ne

Question

a wire of length L and resistance R is now drawn out by pulling such that its new resistance is 15R. what is its new length (assume density remains constant). A. 1.50 L B. 6.67 x 10^-1L C. 2.25 L D. 3.87 L E. 2.5 x 10-1L a wire of length L and resistance R is now drawn out by pulling such that its new resistance is 15R. what is its new length (assume density remains constant). A. 1.50 L B. 6.67 x 10^-1L C. 2.25 L D. 3.87 L E. 2.5 x 10-1L A. 1.50 L B. 6.67 x 10^-1L C. 2.25 L D. 3.87 L E. 2.5 x 10-1L

Explanation / Answer

R = rho*L/A

R1 = rho*L1/A1 = R = rho*L/A1

R2 = rho*L2/A2 = 15R = rho*L'/A2

R2 = 15R2

here volume remain constant

15R = rho * LL'/(A/L')

15R = rho*L'^2*L/A

rho*L/A = R

L' = sqrt(15) =

L' = 3.87 m

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.