A mass m 1 = 5.5 kg rests on a frictionless table and connected by a massless st

Question

A mass m1 = 5.5 kg rests on a frictionless table and connected by a massless string to another mass m2 = 5.6 kg. A force of magnitude F = 43 N pulls m1 to the left a distance d = 0.87 m.

1) How much work is done by the force F on the two block system?

2) How much work is done by the normal force on m1 and m2?

3) What is the final speed of the two blocks?

4) How much work is done by the tension (in-between the blocks) on block m2?

5) What is the tension in the string?

6) What is the NET work done on m1?

Explanation / Answer

1)

Work done = F.S = FD

W = 43x0.87 = 37.41 J

2)

Since angle between normal force and displacement is 90 work done by normal force

Wn = 0

3)

Work done = change in kinetic enrgy of system

37.41 = 0.5(5.5+5.6) V^2

v = 2.6 m/sec

4)

Work done by tension = change in ke of m2

Wt = 18.87 J

5)

Wt = 18.87

Td = 18.87

T = 21.693 N

6)

Net work done on m1 is change in kE of m1

Wm1 = 0.5m1v^2

Wm1 = 18.59 J

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