A fisherman sees rays of light apparently diverging from a point P \' on a fish

Question

A fisherman sees rays of light apparently diverging from a point P' on a fish (see figure below). The fish appears to be at y = 1.6 m below the surface. What is its actual depth? (Take ? = 49.2°.)

This is what the first person who answered did, and it is still wrong. No one has answered this right yet.

here,

From Snell law,

TanI = X/R and TanR = X/A

Where,
i is incident angle
R is real depth
A is apparent depth

If i and r are small angles is small then Tani = Sini, therefore

n = R/A -------------------(1) (n represents the refractive index of light going from air to water)

Solving for Real Depth,

R = n*A
R = 1.33 * 1.6
R = 2.128 m

Explanation / Answer

We know that

Da = Dr/tan

So, Dr = 1.6 *tan(49.2)

= 1.85 m is the real depth

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