8. How long does it take for a charge of 2.90 C to pass through the cross-sectio

Question

8. How long does it take for a charge of 2.90 C to pass through the cross-sectional area of a wire that is carrying a current of 0.37 A ?

9.A net charge of 38 C passes through the cross-sectional area of a wire in 1.8 min . What is the current in the wire?

18. Two 9.3 resistors are connected in parallel, as are two 3.1 resistors. These two combinations are then connected in series in a circuit with a 11 V battery.What is the current in each resistor? What is the voltage across each resistor?

19. Two identical resistors (each with resistance R) are connected together in series and then this combination is wired in parallel to a 26 resistor. If the total equivalent resistance is 14 , what is the value of R?

23. A charged particle travels undeflected through perpendicular electric and magnetic fields whose magnitudes are 1000 N/C and 40 mT , respectively. Find the speed of the particle if it is a proton.Find the speed of the particle if it is an alpha particle. (An alpha particle is a helium nucleus-a positive ion with a double positive charge of +2e.)

Explanation / Answer

8) Apply, I = dQ/dt

==> dt = dQ/I

= 2.9/0.37

= 7.84 s

9) I = dQ/dt

= 38/(1.8*60)

= 0.352 A

18) net resistance, Rnet = 9.3/2 + 3.1/2

= 6.2 ohms

current through the battery, I = V/Rnet

= 11/6.2

= 1.77 A

current through each 9.3 resistors = 1.77/2 = 0.885 A

current through each 3.1 resistors = 1.77/2 = 0.885 A

voltage across each 9.3 resistors = 1.77*(9.3/2) = 8.23 A

voltage across each 3.1 resistors = 1.77*(3.1/2) = 2.77 A

19)

(R/2)*26/(R/2 + 26) = 14

13*R = (R/2 + 26)*14

13*R = (R + 52)*7

13*R = 7*R + 364

R = 364/6

= 60.67 ohms

23) Apply, q*E = q*v*B

v = E/B

= 1000/(40*10^-3)

= 2.5*10^4 m/s

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