R\" means any purine. \"Y means any pyrimidine. \"N\" means any base. The nucleo
ID: 143745 • Letter: R
Question
R" means any purine. "Y means any pyrimidine. "N" means any base. The nucleotide sequence "GCGAC should occur every nucleotide pairs on average. The nucleotide sequence "YGAAAGTG" should occur every nucleotide pairs on average. A DNA molecule consists of 10000 nucleotide pairs. A restriction enzyme cuts it into 26 fragments, one of which is 3000 nucleotide pairs long. 112 g of this DNA were digested with the enzyme, what mass of DNA would be in this fragment? Round your answer to the nearest whole number. ng A DNA molecule consists of 25000 nucleotide pairs. A restriction enzyme cuts it into 9 fragments, one of which is 2000 nucleotide pairs long. If 10 ug of the DNA were digested with the enzyme, what mass of DNA would be in this fragment? Round your answer to the nearest whole number ng For the two fragments in the previous part of the question, how many times more intense will the more whole number bright fragment be than the less bright fragment? Round your answer to the nearest times brighter Click "Validate Answer" when you are satisfied with your answers then follow the instructions that appear Validate AnswerExplanation / Answer
1) The probability of occurrence of any nucleotide is 0.25. So, the nucleotide sequence GCGAC occurs every
= 1/4 × 1/4 × 1/4 × 1/4 × 1/4
= 1/1024
The given nucleotide sequence occurs every 1024 nucleotide pairs.
2) The probability of occurrence of the sequence YGAAAGTG is,
= 1/2 × 1/4 × 1/4 × 1/4 × 1/4 × 1/4 × 1/4 × 1/4
= 1/32768
The sequence occurs every 32768 nucleotide pairs.
3) A DNA molecule with 10000 nucleotide pairs when digested with restriction enzymes, 3000 nucleotide pairs are produced. This corresponds to 30% of the DNA. So when 2 microgram of DNA is digested, we would get (2 × 0.3) 0.6 microgram of DNA.
4) The length of nucleotide in DNA is 25000. Out of this, 2000 base pair long is obtained from digestion by restriction enzyme. The ratio is 0.08. So, when 10 microgram of DNA is digested, we would get (10 × 0.08) 0.8 microgram of DNA.
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