Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

(Be clear and concise. Typing work is strongly suggested. Will thumps up dependi

ID: 1437425 • Letter: #

Question

(Be clear and concise. Typing work is strongly suggested. Will thumps up depending on the quality of work done.) A negatively charged ion moves due north with a speed of 2.2 Times 10^6 m/s at the Earth's equator. What is the magnetic force exerted on this ion? An 89-ohm resistor has a current of 0.51 A and is connected in series with a 130-ohm resistor. What is the emf of the battery to which the resistors are connected? Find the power dissipated in a 39-ohm electric heater connected to a 120-V outlet.

Explanation / Answer

1a)
q = 1.6 * 10^-19 C
v = 2.2 * 10^6 m/s
= 0
F = q*v*B*sin()
F = 0 N

1b)
Req = 89 + 130 = 219 ohm
V = I*Req
V = 0.51 * 219 V
V = 111.7 V
Emf of the battery to which Resistors are connected, V = 111.7 V


1c)
Power dissipated in Resistor is given by,
P = V^2/R
P = 120^2/39 W
P = 369.2 W