The graph below shows an oscillation trace of a sinusoidal voltage signal as a f
ID: 1436871 • Letter: T
Question
The graph below shows an oscillation trace of a sinusoidal voltage signal as a function of time, For the graph shown below the vertical volts per division it 1.0 V/div and the horizontal time per division is 2.0 msec/div. For this signal: What is the peak-to-peak voltage of the signal? What is the voltage amplitude (or V_max) in volts of the signal? What is the rms value of the signal in volts? What is the period of the signal in milliseconds? What is the frequency of the signal? (Include the units.)Explanation / Answer
(a) peak to peak voltage is 6 V
(b) Voltage amplitude is 3 V
(c) RMS value of voltage =voltage amplitude / (2)1/2 = 3 / (2)1/2 = 2.12 V
(d) time peroid is T = 5 horizontal divisions = 5 x 2 millisec = 10 ms
(e) frequency of signal f = 1 / T = 1 / (10 x 10-3 ) = 100 Hz
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