Electrons and protons are passing through a small hollow tube. calculate the cur

Question

Electrons and protons are passing through a small hollow tube. calculate the current and/or indicate its direction in each of the following situations.

A) A total charge of Q = 1.5C passes through the tube toward the right in a time of 1s.

B) A total charge of Q = -1.5C passes through the tube towards the right in a time of 1s.

C) A total of 3 protons and 2 electrons pass through the tube towards the right in a time of 1 nanosecond.

D) 3 protons pass through towards the right while 2 electrons pass through the tube towards the left in a time of 1 nanosecond

Explanation / Answer

We know from the defination of electric current that,

I = Q/t

Direction of current is same as the flow of positive charge.

A) Q = + 1.5 C ; t = 1 s

I = Q/t = 1.5 C/1s = 1.5 A

Hence, I = 1.5 A towards right.

B)Q = -1.5 C and t = 1 s

I = Q/t = -1.5 C/1 s = -1.5 A

Hence, I = 1.5 A towards left.

C) t = 1 ns = 10-9 s

In this case, the net charge is that of 5 proton. (Q = 3qp - 2qe = 1qp )

we know that, e = 8 x 10-19 C ;

I = Q/t = 8 x 10-19 C /10-9 s = 8 x 10-10 A

Hence, I = 8 x 10-10 A towards right.

D) In this case, the net charge will be, that of 1 proton

Q = 1.6 x 10-19 and t = 10-9 s

I = Q/t = 1.6 x 10-19 / 10-9 = 1.6 x 10-10 A

Hence, I = 1.6 x 10-10 A towards right.

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