oo T-Mobile Wi-Fi 7:45 PM a usb06ca.theexpertta.com DC circuits 2 Begin Date: 2/
ID: 1436401 • Letter: O
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oo T-Mobile Wi-Fi 7:45 PM a usb06ca.theexpertta.com DC circuits 2 Begin Date: 2/10/2016 12:00:00 AM -Due Date: 3/13/2016 11:00:00 PM End Date: 3/162016 12:00:00 AM 33% Part (a) Find the time constant of the discharge circuit, in seconds. 33% Part (b) Calculate the temperature increase ofthe resistor, in degrees celsius. given that its mass is 2.50 g and its specific heat is 1.67 kJ kglC. Assume all the energy dissipated by the capacitor goes into heating it. 33% Part (c) Calculate the new resistance of the resistor, in ohms, after it has warmed, assuming it is made of pure carbon, whose temperature coefficient of resistivity is-5.0 x 10 yoC.Explanation / Answer
(a) time constant is
T = Rc = 30.4 * 10^3 ( 570 * 10^-6 ) = 17.32 s
)b)
Q = mc del T
VIT = mc del t
830 V ( 830 V/30.4 * 10^3 ) ( 17.32 s) = 2.5 * 10^-3 kg ( 1.67* 10^3) del t
del t = 94 C
---------------------------------------------------------------
R = Ro ( 1+ alpha del t)
= 30.4 * 10^3 ( 1+ (- 5 * 10^-4 ) ( 94)
=28.97 k ohm
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