A converging lens has a focal length of 12.0 cm. If an upright object is placed

Question

A converging lens has a focal length of 12.0 cm. If an upright object is placed 36.0cm in front of the lens, the resulting image will be?
(a) real, upright, and magnified comapred to the original object.
(b) real, inverted, and smaller when comapred to the original object.
(c) virtual, inverted, and smaller when comapred to the original object.
(d) real, inverted, and magnified comapred to the original object.
(e) real, inverted, and the same size when comapred to the original object.

I think the answer is (b) but I'm not sure.

Explanation / Answer

Answer is B.
When the object is located at a location beyond the 2F point, the image will always be located somewhere in between the 2F point and the focal point (F) on the other side of the lens. Regardless of exactly where the object is located, the image will be located in this specified region. In this case, the image will be an inverted image. That is to say, if the object is right side up, then the image is upside down. In this case, the image is reduced in size; in other words, the image dimensions are smaller than the object dimensions. If the object is a six-foot tall person, then the image is less than six feet tall. The term magnification was introduced; the magnification is the ratio of the height of the object to the height of the image. In this case, the magnification is a number with an absolute value less than 1. Finally, the image is a real image.

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