4. A rectangular coil of N turns has width W and length L. It moves with velocit
ID: 1435554 • Letter: 4
Question
4. A rectangular coil of N turns has width W and length L. It moves with velocity v as it enters a region of uniform magnetic field Bstatic (see figure at right). The coil has resistance R and mass M. (a) In what direction does the induced current circulate in the coil when it enters the magnetic field? (b) What is the magnitude of the induced EMF and current in the coil? (c) While there is an induced current in the coil, what is the direction of the force exerted by Bstatic on the bottom side of the coil? (d) While there is an induced current in the coil, what is the magnitude of the force exerted by Bstatic on the bottom side of the coil? (e) What would be your answer to part 3(c) (direction of the force) if Bstatic was reversed, i.e., into the page rather than out of it? Explain. rather than out of it? Explairn.Explanation / Answer
Suppose in the given condition,
B is inside the plane of paper and velocity is in the positive x-direction so direction of induce currernt is verical (upward) direction i.e. towards the positive y-axis.
= B*L*v
Where, B= magnetic field, L = length of the coil and v = velocity of the coil
The magnitude of the induced current in the coil can be calculate by using formula,
= L (di/dt) here L = self inductance
Therefore
di = (/L ) dt
F = q (v * B) Here q is charge (Lorent’z force formula)
Direction of force is clockwise and downward (towards negative y axis)
(Note : we can also use screw rule to find the direction of force)
F = q (v * B) Here q is charge (Lorent’z force formula)
Direction of force is clockwise and downward (towards negative y axis)
(Note : we can also use screw rule to find the direction of force)
i.e. Direction of force is anticlockwise and in upward direction (towards positive y axis)
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